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Copy path25. Reverse Nodes in k-Group
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25. Reverse Nodes in k-Group
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/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
int length(ListNode* head){
int cnt = 0;
while(head != NULL){
head = head -> next;
cnt++;
}
return cnt;
}
ListNode* reverseKGroup(ListNode* head, int k) {
//base case
if(head == NULL)
{
return head;
}
int len = length(head);
if(k > len)
return head;
ListNode* prev = NULL;
ListNode* curr = head;
ListNode* forward = NULL;
int cnt = 0;
while(cnt < k && curr != NULL)
{
forward = curr -> next;
curr -> next = prev;
prev = curr;
curr = forward;
cnt++;
}
if(forward != NULL)
{
head -> next = reverseKGroup(forward, k);
}
return prev;
}
};