How to read elment-piecewisely for a vector from html UI selection input

[idealkindom]

I tried with failure on this. The codes are behind:

#pre
n = ? {5}
#hide
Mt = vector(n)
#def Mtt$(j$)
'select:
'<span><select name="target'j$'"></span>
#end def
#def Mtj$(j$)
'<p id="target1"> Values:'Mt.j$ = ? {1}'</p>
#end def
#post
#for j = 1 : n
#val
'The 'j'th element value of the vector:
#equ
#input
Mtt$(j)
'<option value="1">x=1</option>
'<option value="2">x=2</option>
'<option value="3">x=3</option>
'<option value="4">x=4</option>
'<option value="5">x=5</option>
'</select>
Mtj$(j)
#hide
#loop
#post
#for j = 1 : n
Mt.j
#loop

Or if there is a way to batch input of elements' value with Html UI after prescription of the length of the the vector,i.e., n, then it could be better.

[strsthapa]

Iam not sure you mean this or not;

[idealkindom]

Iam not sure you mean this or not;

Thks , you really did quite a good job. However, if you tried for several times you could find the input experience is not so good, for you click flip to choose the ith elem the choice boxes choosen before also changes, though the results could be defined with selection. Right? I think we have to change also the "target" string in the #def macro block.

[idealkindom]

Iam not sure you mean this or not;

I modified the code somehow. Still the effect is unsatisfactory like the screenshot I attached.

[idealkindom]

Iam not sure you mean this or not;

The code:

#def S$(s$)
'Select value for elem: <select name="target1">
'<option value="1">x=1</option>
'<option value="2">x=2</option>
'<option value="3">x=3</option>
'</select>
'<p id="target1" style="display:none"> Values:'s$ = ? {2}'</p>
#end def
n = ? {5}
#hide
h = vector(n)
#post
#pre
#hide
#for i = 1 : n
#post
#val
'select 'i'th elm:<br/>
#input
#show
S$(h.i) #{2}
#hide
#loop
#equ
#post
h

[strsthapa]

To change the target string we can pass another variable on macro but it will restrict the loop usage for vector since output are stored #{} of the called function location which will be only one within the loop.

[idealkindom]

To change the target string we can pass another variable on macro but it will restrict the loop usage for vector since output are stored #{} of the called function location which will be only one within the loop.

How about make the lenght of the vector a variable from input,i.e.,let put n=?{6} a=vector(n)

[idealkindom]

To change the target string we can pass another variable on macro but it will restrict the loop usage for vector since output are stored #{} of the called function location which will be only one within the loop.

Yes, it could only allow for select the elem value one by one pertumated by the ascending order of elem's index, instead of selecting values for all the elements by once.