correct way to interact and continue

[GiorgioBurbanelli89]

According to this image, what is the correct way to execute this operation, each element of a only adds 1 if it is not 0, when it is 0 it continues iterating without using any operation
A = [0; 0; 1]
B = vector(len(A))

#for i = 1 : len(A)
c = A.i

#if c ≡ 0
    'No hacer nada si c es 0'
#else
    B.i = A.i + 1
#end if

#loop

B

A = [0; 0; 1]
B = vector(len(A))
#for i = 1 : len(A)
c = A.i
#if c ≡ 0
#continue
#end if
B.i = A.i + 1
#loop
B

A = [0; 0; 1]
B = vector(len(A))
#for i = 1 : len(A)
c = A.i
#if c ≡ 0
#continue
B.i = A.i + 1
#end if
#loop
B

The first way is one way but I want it to be with #continue

[marcostrmuniz]

Could you please paste this code in the comments?

[GiorgioBurbanelli89]

A = [0; 0; 1]
B = vector(len(A))
#for i = 1 : len(A)
c = A.i
#if c ≡ 0
#continue
#end if
B.i = A.i + 1
#loop
B

A = [0; 0; 1]
B = vector(len(A))
#for i = 1 : len(A)
c = A.i
#if c ≡ 0
#continue
B.i = A.i + 1
#end if
#loop
B

[Proektsoftbg]

Hi!

Thanks for posting.
The topmost version is correct, but it seems that there is some bug with #continue. I will look at it and will fix it. The shortest and cleanest code you can use is to reverse the condition and put the operation inside:

A = [0; 0; 1]
B = vector(len(A))
#for i = 1 : len(A)
c = A.i
#if c ≠ 0
B.i = A.i + 1
#end if
#loop
B

But you are right. It also should work with #continue.

[GiorgioBurbanelli89]

The first way works the second way doesn't

[Proektsoftbg]

Yes, that is right. When I added the new #for and #while loops, I forgot to add support for #continue with them. Now I fixed, thanks to your feedback.

Tomorrow I will update the program. Now it is late here. Time to go to bed. :)

[GiorgioBurbanelli89]

and it updates on my calcpad or should I download an update?