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Day-18-H-Index II.cpp
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Day-18-H-Index II.cpp
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Given an array of citations sorted in ascending order (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.
According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."
Example:
Input: citations = [0,1,3,5,6]
Output: 3
Explanation: [0,1,3,5,6] means the researcher has 5 papers in total and each of them had
received 0, 1, 3, 5, 6 citations respectively.
Since the researcher has 3 papers with at least 3 citations each and the remaining
two with no more than 3 citations each, her h-index is 3.
Note:
If there are several possible values for h, the maximum one is taken as the h-index.
Follow up:
This is a follow up problem to H-Index, where citations is now guaranteed to be sorted in ascending order.
Could you solve it in logarithmic time complexity?
class Solution {
public:
int hIndex(vector<int>& citations) {
int n=citations.size();
if(!n) return 0;
int si=0, ei=n-1, mid;
while(si<=ei){
mid=si+(ei-si)/2;
if(citations[mid]==n-mid) return citations[mid];
else if(citations[mid]>n-mid) ei=mid-1;
else si=mid+1;
}
return n-si;
}
};