-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathbinary-tree-zigzag-level-order-traversal.h
54 lines (43 loc) · 1.44 KB
/
binary-tree-zigzag-level-order-traversal.h
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
#ifndef BINARY_TREE_ZIGZAG_LEVEL_ORDER_TRAVERSAL_H_
#define BINARY_TREE_ZIGZAG_LEVEL_ORDER_TRAVERSAL_H_
#include <algorithm>
#include <deque>
#include <iterator>
#include <vector>
#include "tree-node.h"
namespace solution {
std::vector<std::vector<int>> zigzagLevelOrder(TreeNode* root) {
// with deque
// Runtime: 3 ms, faster than 75.91% of C++ online submissions for Binary Tree Zigzag Level Order Traversal.
// Memory Usage: 12.1 MB, less than 46.98% of C++ online submissions for Binary Tree Zigzag Level Order Traversal.
//
std::vector<std::vector<int>> result;
if (root == nullptr) return result;
std::deque<TreeNode*> deque;
deque.push_back(root);
auto reversed{false};
while (!deque.empty()) {
std::vector<int> v;
if (reversed) {
std::transform(deque.crbegin(), deque.crend(), std::back_inserter(v),
[](const TreeNode* node) { return node->val; });
} else {
std::transform(deque.cbegin(), deque.cend(), std::back_inserter(v),
[](const TreeNode* node) { return node->val; });
}
result.push_back(v);
auto size = deque.size();
reversed = !reversed;
for (auto i{0}; i < size; ++i) {
auto node = deque[i];
if (node->left) deque.push_back(node->left);
if (node->right) deque.push_back(node->right);
}
while (size--) {
deque.pop_front();
}
}
return result;
}
}
#endif // !BINARY_TREE_ZIGZAG_LEVEL_ORDER_TRAVERSAL_H_