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18. 4Sum
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18. 4Sum
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class Solution {
public List<List<Integer>> fourSum(int[] nums, int target) {
List<List<Integer>> result = new ArrayList<>();
if (nums == null || nums.length < 4) {
return result;
}
Arrays.sort(nums);
int n = nums.length;
for (int i = 0; i < n - 3; i++) {
if (i > 0 && nums[i] == nums[i - 1]) continue; // Skip duplicates
for (int j = i + 1; j < n - 2; j++) {
if (j > i + 1 && nums[j] == nums[j - 1]) continue; // Skip duplicates
int left = j + 1;
int right = n - 1;
while (left < right) {
long sum = (long) nums[i] + nums[j] + nums[left] + nums[right];
if (sum == target) {
result.add(Arrays.asList(nums[i], nums[j], nums[left], nums[right]));
while (left < right && nums[left] == nums[left + 1]) left++; // Skip duplicates
while (left < right && nums[right] == nums[right - 1]) right--; // Skip duplicates
left++;
right--;
} else if (sum < target) {
left++;
} else {
right--;
}
}
}
}
return result;
}
}