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As stated in the title, when calling this advance_jumper() it leaves "=UltiSnips#JumpForwards()" in the commandline. I think this is a little bit annoying, because when I have a snippet that uses this function I have this useless information at the bottom of my screen. I found a way to fix this though: Using
does not leave it, because UltiSnips binds g:UltiSnipsJumpForwardTrigger and g:UltiSnipsJumpBackwardTrigger with the silent flag. When using just the feedkeys method, it is not silent, thus leaves this in the command line. I'm note sure if there are any complications for other use cases, but for me it works fine. Maybe there is also a better solution for this.
The text was updated successfully, but these errors were encountered:
As stated in the title, when calling this advance_jumper() it leaves "=UltiSnips#JumpForwards()" in the commandline. I think this is a little bit annoying, because when I have a snippet that uses this function I have this useless information at the bottom of my screen. I found a way to fix this though: Using
inside the _make_jumper_jump() method of px.snippets instead of
does not leave it, because UltiSnips binds
g:UltiSnipsJumpForwardTrigger
andg:UltiSnipsJumpBackwardTrigger
with the silent flag. When using just the feedkeys method, it is not silent, thus leaves this in the command line. I'm note sure if there are any complications for other use cases, but for me it works fine. Maybe there is also a better solution for this.The text was updated successfully, but these errors were encountered: